Calcul alg├ębrique

Factorisation


Factoriser les expressions suivantes:
$ A=(2x-5)^2-16$
$ B=(5x-3)(7x+4)-(5x-3)$

Solution:


$A=(2x-5)^2-16
=\Big((2x-5)-4\Big)\tm\Big((2x-5)+4\Big)
=\left( 2x-9\rp\left( 2x-1\rp
$B=(5x-3)(7x+4)-(5x-3)
=(5x-3)\Big( (7x+4)-1 \Big)
=(5x-3)(7x+3)


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